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lim as x approaches 0^- ((x-(2(sqrt(x)))+1)/((sqrt(x))+1) Can someone start me off with this please?
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Assuming we are finding limits in the reals And since we have sqrt{x} That means x>0 But you say you are approaching 0 from the left Which means you are getting close to 0 from the negative side Which means what .... Do you know?
oops x>=0 whatever lol
still confused a little
Can x be less than 0?
yes
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So if x<0 then sqrt{x} is real?
still confused. I'm a visual person
\[\sqrt{-0.00001}=?\] Is this number real?
it's imaginary
So is that number inside the square root less than 0?
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no?
All negative numbers are less than 0
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