If the pyramid in the previous problem had a Volume of 125,000ft3, length of 75 fee, and height of 100 feet, how wide was it?

Question

callisto · Answer

@NeedMuchHelp What is the formula you've got for your previous question?

anonymous · Answer

V = 1/3 lwh

callisto · Answer

What about the answer to your previous question, the one with w (width) as the subject?

parthkohli · Answer

Hmm.

$ \color{Black}{\Rightarrow 125,000 = {1 \over 3} \times 75 \times 100 \times w}$

Can you solve this equation?

anonymous · Answer

Put the values of V, l and h in the equations.

125000= 1/3 * 75 * 100 * w

Now can you solve it?

anonymous · Answer

im confused on how to.

callisto · Answer

@NeedMuchHelp May I know what you've got in your previous question? The answer to your previous question helps a lot in doing this question.

anonymous · Answer

first divide by 100 on both sides of the equation. It becomes
1250 = 1/3 * 75 *w

1/3*75 = 25
So, 
1250 = 25 * w 

Now do you know how to do it?

anonymous · Answer

yes