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if \[f(x)=3x+12/2x-12 ,\] what does f(x) approach as x goes infinitely larger ??
@rebeccaskell94 come on help me
as x goes infinitely larger then 3x>>12 and 2x>>-12 what now?
\[\huge{\frac{3x+12}{2x-12}}\] what r u getting simplified
\[\huge{\frac{3(x+4)}{2(x-6)}}\] \[\huge{\frac{3}{2}*\frac{x+4}{x-6}}\] Can u find the limit tends to ?
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