(3x^ 2a - 4y^ a z ^3a)^ 2 how to solce perfect square

Question

amistre64 · Answer

$$(a+b)^2=a^2+2ab+b^2$$

anonymous · Answer

is this a formula? but whats a & b

amistre64 · Answer

$$(ab-mn)^2=(ab)^2-2(abmn)+(mn)^2$$

amistre64 · Answer

yes, its a formula

the first part is just a single value regardless of how convoluted it appears :)  same with the second value

anonymous · Answer

oh okay. but can you explain to me step by step on how to solve them because am really lost

amistre64 · Answer

(3x^ 2a - 4y^ a z ^3a)^ 2 =

(3x^ 2a)^2

  - 2(3x^ 2a)(4y^ a z ^3a)
 
     +(4y^ a z ^3a)^2

amistre64 · Answer

define your first term (a)  and your last term (b)  and fill them into the general formula is all it amounts to

and dont try to do it all at once, just work on it piece by piece

amistre64 · Answer

you might have been taught a method called FOIL .... thats all it is

anonymous · Answer

oh okay and when you put the equation into the formula given do you have to put it in lowest terms?
 or what happens next?

amistre64 · Answer

most likely you have to eventually get all like terms together and neatened up yes

amistre64 · Answer

but i cant really decipher the post well enough to guide you further with it

anonymous · Answer

oh okay but for this kind of equation how would you set  it up to foil it

amistre64 · Answer

take the general equation:$$(a+b)^2$$or if to keep things similar lets go with:$$(a-b)^2$$

recall that any number squared is just multiplying itself; 

3^2 = 3*3
4^2 = 4*4
x^2 = x*x

$$(a-b)^2=(a-b)(a-b)$$