Find all the values of θ, 0 ≤ θ ≤ 2pi, for which 4sin^2 = 3. Description of how you do it would be golden :). Cheers.

Question

Find all the values of θ, 0 ≤ θ ≤ 2pi, for which 4sin^2 = 3.  Description of how you do it would be golden :).  Cheers.

anonymous · Answer

Actually, scratch that.  All i need to know is how to find what θ is for 4sin^2 = 3.

parthkohli · Answer

$ \color{Black}{\Rightarrow \sin^2 \theta = \Large {3 \over 4} }$

$ \color{Black}{\Rightarrow \sin \theta =\Large {\sqrt{3} \over \sqrt4} }$
 
Please continue from here, as I gotta go

anonymous · Answer

Tyvm!  I hit a brick wall with this question... cheers.