Question

Gravel is dropped on a conveyor belt at the rate of 0.5kg/s. The extra force in Newton required to keep the belt moving at 2m/s, is

Answer 1

The rate of gravel being dropped is \[\frac{\Delta m}{\Delta t}=\frac{0.5kg}{1s}\]The extra force required to keep the belt moving with velocity v is\[F=v\frac{\Delta m}{\Delta t}=2m/s \frac{0.5kg}{1s}=1N\]