Question

Write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3).

Answer 1

can you tell me the slope?

Answer 2

7

Answer 3

great m=7, x1=1 , y1=-3

this will be your equation for the line:
y-y1=m(x-x1)

Answer 4

plug it in and simplify accordingly

Answer 5

y - (-3) = 7 (x -1)

Answer 6

then you subtract -3

Answer 7

y - (-3) = 7 (x -1)
y +3 = 7 (x -1)

Answer 8

y +3 = 7x - 7
y = 7x - 7-3
y = 7x - 10

yes you do subtract the 3

Answer 9

oh ok

Answer 10

do you do the same for Write the equation of a line parallel to the line y = 3, that passes through the point (1, 6).

Answer 11

well yes you find the slope.

Answer 12

and then use the point given to you where

x1=1
y1=6
m=slope

Answer 13

The only thing you need to find is the slope and then you just plug in everything to this equation:

y-y1=m(x-x1)

Answer 14

so it'll b written as this y - 6 = m (x - 1)

Answer 15

yes all you need is the slope but y=3 has no slope so
m=0

Answer 16

so that means the whole right side becomes zero

Answer 17

y - 6 = m (x - 1)
y - 6 = 0 (x - 1)
y - 6 = 0

then you add 6 to both sides

y = 6


this is the equation you have now

Answer 18

oh ohk..yea i worked it out.. i got it now