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70 ounces of fertilizer cover 2800 square feet of lawn. How many ounces would be required to cover a 5800 square foot lawn?
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5800/(2800/70) 145ounces
You have the following factor ( 70 ounces / 2800 sqft ) = (1 ounces / 40 sqft) to cover 5800 sqft you must multp 5800 sqft by (1 ounces / 40 sqft) = 145 ounces
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