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find global max and min of f(x) = x-2ln (x-1),0
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sorry there must be some mistake here domain of \(\ln(x-1)\) is \(x>1\)
how about \[f(x) x-2\ln(x-1), 0\le x \le2 \]
the problem is that the domain of your function does not include \((0,1]\)
ok
f(x)= x-2ln(x+1)\[f(x)= x-2\ln(x+1)0\le x \le2 \]
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help please!!
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