Question

solve. then round answer to the nearest hundredth. 6^x-3=52

Answer 1

\[6^{x-3} = 52\]You will need to use logarithms to solve this one

Answer 2

Specifically, you will need to use the property of logarithms such that will allow you to work with the exponent:

So, if you have \[x^y\], if you take the log of this you obtain:
\[log_a(x^y) = y * log_a(x)\]The exponent now becomes a factor in the product

Answer 3

For your equation, you will want to take the logarithm of both sides, then you can solve for x. You can use any base for the logarithm: \[log_a\] I'm sure you're familiar with the concept of logarithms, but here is nice way to remember what it does: you can say that when you have the expression: \[log_ab = x\]You are looking for the number you raise 'a' to in order to obtain 'b' is 'x'. \[a^x = b\]

\[log_28=3\]The number you raise 2 to in order to obtain the value 8, is 3. \[2^3 = 8\]

Answer 4

Does this seem familiar or helpful?

Answer 5

yes..

Answer 6

OK, cool, I see that you had a similar question - http://openstudy.com/users/coolaidd#/updates/4fff44afe4b09082c0707aad

Answer 7

thanks

Answer 8

Do you think you can solve this problem?

Answer 9

log_5 x=3
x = 5^3 = 125

Answer 10

sorry!

Answer 11

6^(x - 3) = 52
(x - 3) ln 6 = ln 52
x - 3 = ln 52/ln 6
x = 3 + ln 52/ln 6 ≈ 5.20523

Answer 12

Yeah, nice!

Answer 13

thanks! :)

Answer 14

Sure, good luck with the rest of your studies! Maybe you can help with some questions even ;)