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Mathematics 13 Online
OpenStudy (anonymous):

Given that the P(A) = 0.32, P(B) = 0.34, and = 0.56, find the P( B ' | A' ).

OpenStudy (zarkon):

did you mean to have \[P(A\cup B)=.56\]

OpenStudy (zarkon):

or...same thing..\[P(A\text{ or }B)=.56\]

OpenStudy (queelius):

Zarkon, btw, "and" is intersection, not union.

OpenStudy (zarkon):

yes..I know...i'm using OR

OpenStudy (queelius):

I guess I'm a little confused then. I would have thought it was P(A and B) = 0.56.

OpenStudy (zarkon):

no...\[\cup\] is the same as OR in probability

OpenStudy (zarkon):

\(\cap\) is intersection...and AND

OpenStudy (queelius):

I realize that. That's not exactly where my confusion lies. Why are you using OR in the first place?

OpenStudy (zarkon):

it cant be AND...that would be a contadiction

OpenStudy (zarkon):

for any events \(A,B\) \[P(A\cap B)\le P(A)\] and \[P(A\cap B)\le P(B)\]

OpenStudy (queelius):

Ah, yes. Very true.

OpenStudy (queelius):

His usage of the word "and" got me started off on the wrong track. Thank you.

OpenStudy (zarkon):

ah...ic

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