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Given that the P(A) = 0.32, P(B) = 0.34, and = 0.56, find the P( B ' | A' ).
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did you mean to have \[P(A\cup B)=.56\]
or...same thing..\[P(A\text{ or }B)=.56\]
Zarkon, btw, "and" is intersection, not union.
yes..I know...i'm using OR
I guess I'm a little confused then. I would have thought it was P(A and B) = 0.56.
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no...\[\cup\] is the same as OR in probability
\(\cap\) is intersection...and AND
I realize that. That's not exactly where my confusion lies. Why are you using OR in the first place?
it cant be AND...that would be a contadiction
for any events \(A,B\) \[P(A\cap B)\le P(A)\] and \[P(A\cap B)\le P(B)\]
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Ah, yes. Very true.
His usage of the word "and" got me started off on the wrong track. Thank you.
ah...ic
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