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Intergrate. sqrt(5-4x-x^2)
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\[\int\limits_{}^{}\sqrt{5-4x-x^2}\]
Looks like you should be able to complete the square, then use trig-sub
\(\large \sqrt{5-4x-x^2}=\sqrt{-1[x^2+4x-5]}=\sqrt{-1[(x^2+4x+4)-4-5]} \) \(\large =\sqrt{-1[(x+2)^2-9]}=\sqrt{9-(x+2)^2}=\sqrt{3^2-(x+2)^2} \)
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