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Log(sub 2) 3 + log(sub 2) a = log(sub 2) 20
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\[\log_2(3)+\log_2(a)=\log_2(20)\]?
start by combining the logs on the left using \[\log(x)+\log(y)=\log(xy)\] you get \[\log_2(3a)=\log(20)\]
then since log is a one to one function, this means \[3a=20\] solve for \(a\)
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