Question

9^2q-6=3^q+6

Answer 1

this is

\[(3^2)^{2q - 6} = 3^{q + 6}\]

or

\[3^{4q - 12} = 3^{ q + 6}\]

since they are now the same base equate the powers

4q - 12 = q + 6

3q = 18

solve for q

Answer 2

hehe u got it :D