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Choose the equation of the line passing through the point (3, -2) and parallel to y = 3x - 6.
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y = 3x - 11
here is the explanation since it is parallel to y = 3x -6 the gradient = 3 so the general equation will be y = 3x + c now to find c substitute the coordinates and you get -2 = 9 + c c = -11 therefore the equation is y = 3x -11
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