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Mathematics 13 Online
OpenStudy (anonymous):

Need Help with figuring out angles, need step by step

OpenStudy (lgbasallote):

what do you mean? what do you have in mind?

OpenStudy (anonymous):

OpenStudy (lgbasallote):

hah lol

OpenStudy (anonymous):

I have no idea how to start with that, I tired figuring out how to solve by finding the arcs.. but i dont know the circumference so i cant find it

OpenStudy (lgbasallote):

we're looking for 1,2,3,4,5 right?

OpenStudy (anonymous):

oh yes, correct sorry. mangle1 and mangle2 mangle3 m arc CF mangle4 mangle5 m arc AE

OpenStudy (anonymous):

thats what i need to find

OpenStudy (anonymous):

but idk how to because i dont know the circumference, and i dont know how to find it

OpenStudy (lgbasallote):

arc AC = 45 right?

OpenStudy (anonymous):

correct

OpenStudy (lgbasallote):

and these are equal right? |dw:1342179114506:dw|

OpenStudy (anonymous):

are they??

OpenStudy (lgbasallote):

im asking lol..i dont recall this much...arent they?

OpenStudy (anonymous):

crap i thought you knew.. idk:/

OpenStudy (lgbasallote):

lol i remember they are.

OpenStudy (anonymous):

okay.. think they are

OpenStudy (anonymous):

and hes gone-.- can someone help me?

OpenStudy (callisto):

OpenStudy (callisto):

First, draw EP, FP , and CP. angle EPB = 90 angle BPF = 90 angle APC = 45 Got it?

OpenStudy (callisto):

That's just the start..

OpenStudy (anonymous):

yeah got that part now makes sense

OpenStudy (callisto):

Okay. EP = BP = FP = CP = AP (radii) Agree?

OpenStudy (anonymous):

yea i agree

OpenStudy (callisto):

Good. Now, consider triangle EPB angle PEB = angle PBE (base angle, isos triangle) Got this part?

OpenStudy (anonymous):

yes

OpenStudy (callisto):

In triangle EPB, angle EBP = (180 - angle EPB) / 2 = (180-90) / 2 = ...?

OpenStudy (anonymous):

2= 90....?

OpenStudy (callisto):

Nope. angle EBP = (180 - angle EPB) / 2 (angle sum of triangle) Got this part?

OpenStudy (anonymous):

oh okay

OpenStudy (callisto):

So, angle EBP = (180 - angle EPB) / 2 (angle sum of triangle) = (180-90) / 2 = ...?

OpenStudy (anonymous):

45!

OpenStudy (anonymous):

what now?

OpenStudy (callisto):

Since 5 is angle EBP, what is 5?

OpenStudy (anonymous):

5=45

OpenStudy (callisto):

Yes. Angle PEB = angle EBP, what is angle PEB?

OpenStudy (anonymous):

45

OpenStudy (callisto):

Angle FBD = angle PED (angles at alt. segment) Got it?

OpenStudy (callisto):

*Angle FBD = angle PEB

OpenStudy (anonymous):

wait how are they equal? thats a bit confusing

OpenStudy (callisto):

|dw:1342180730898:dw| b = a (angles at alt segment) It'a a property of tangent to the circle.

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