In guinea pigs, dark hair (D) is dominant over light hair (d) and curly hair (C) is dominant over smooth hair (c). Complete a dihybrid cross for parents with the genotypes: DdCc × DdCc and answer the following in complete sentences. Describe how you would set up a Punnett square for this cross. List the likelihood of each possible offspring genotype. List the likelihood of each possible offspring phenotype.
if you copy and paste off yahoo ill know
http://bit.ly/PVqgcu That is the punnet square you want, just change the letters around. Genotypes are the "genes" of the offspring, while phenotypes are the "ph"ysical characteristics. Genotypes: DDCC (1/16) - Dark Curly DDCc (2/16) - Dark Curly DdCC (2/16) - Dark Curly DdCc (4/16) - Dark Curly DDcc (1/16) - Dark Smooth Ddcc (2/16) - Dark Smooth ddCC (1/16) - Light Curly ddCc (2/16) - Light Curly ddcc (1/16) - Light Smooth You can figure out the phenotypes, just add the fractions of the same physical features together.
LOST!!!!
What do you mean? What you you confused about?
how would you set up a punnet square
You know how to do quadratics in math, right? like ax^2+bx+c?
no
im in geomerty
going into algebra 2
im in 9th grade
hmmm... did you take algebra 1?
yes
but i barely passed same with geometry
there you go! :) it was in algebra one! they look like : \[x ^{2}+x+1\]
Well, I'll start explaining. If you look at the link I gave you, the top side and the left side have letters on them. These are the "possible combinations" that you're going to use.
ok
How you get them is by starting with the DdCc. And we find our first value |dw:1342192810315:dw|
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