Question

what is y^2-3y-2/y^2+5y+6 divided by y^2+2y-8/y^2+y-12 ?

Answer 1

\[y^{2}-3y-2/y^{2}+5y+6 \div y^{2}+2y-8/y ^{2}+y-12\]

Answer 2

that it?

Answer 3

your problem I mean

Answer 4

factor both fractions... then rewrite the division of fractions into multiplying by reciprocals. then cancel common factors.. what u got so far?

Answer 5

(y-1) / (y+2)(y+3) x (y-3) = (y-1)(y-3) / (y+2)(y+3)

Answer 6

Thats the answer.

Answer 7

@Ledah yes that's the proble,

@Isaacisbeast123 thanks :D

Answer 8

\[\frac{y^2-3y-2}{y^2+5y+6} \times \frac{y^2+2y-8}{y^2+y-12}\]