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the perimeter of a rectangle with length, l and width, w is given by P = 2w + 2l . If the perimeter fo a certain rectangle is 105 ft and the length is 35 ft, what is the width?
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\( \color{Black}{\Rightarrow 105 = 2w + 2(35)}\) Are you able to solve the equation for \(w\)? :)
ok i didn't realize it was 2(35) duh i was just putting 35 ok let me see i gotta do it on paper
Hmm sure
ok so i got 105 = 2(17.5) + 2(35) is this correct
that is correct
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thank you
You're welcome!
what!!!!
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