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Mathematics 15 Online
OpenStudy (anonymous):

For what values of p is 4x^2+px+49=0 a perfect square? b^2-4ac=0 p^2-4(4)(49)=0 p^2-784=0 p^2=784 p=+-28???

OpenStudy (anonymous):

completely right

OpenStudy (anonymous):

I thought so too, but by text give the answer +-14

OpenStudy (anonymous):

i can assure u +-28 is your answer

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