Question

which of the following functions has a maximum y-value of 2?
a. y=2(x+1)^2+3
b. y=3(x+1)^2+2
c. y=-3(x+1)^2+2
d. y=-(x-2)^2+3

Answer 1

\((x+1)^2\geq 0\) so \(-3(x+1)^2\leq 0\) so \(-3(x+1)^2+2\leq 2\)

Answer 2

as usual the answer is C

Answer 3

thanks for the help!