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Mathematics 22 Online
OpenStudy (anonymous):

PLEASE HELP URGENT!

OpenStudy (anonymous):

simplify the square root of 49a^4 7a 7a^2 7a a squared 7a^2 a squared

OpenStudy (anonymous):

i think it's 7a^2

OpenStudy (anonymous):

am i right??

OpenStudy (anonymous):

we are going to use the property of sqrt(ab) =sqrt(a)*sqrt(b) so in your case we have sqrt(49a^4) = sqrt(49)*sqrt(a^4) = 7a^2 so your right :)

OpenStudy (anonymous):

yeah :) stay turned i HATE this module lost of questions :(

OpenStudy (anonymous):

you could do it just keep practicing

OpenStudy (anonymous):

i already did most of them here's another Q

OpenStudy (anonymous):

HELP PLEASE

OpenStudy (anonymous):

ok so we have sqrt(z^7)right just try to think for this one you know sqrt(z^2) is just z correct

OpenStudy (anonymous):

z z^3 squared?

OpenStudy (anonymous):

so lets just right z^7 as z^2*z^2*z^2*z do you see what i am trying to do?

OpenStudy (anonymous):

ok i see now it's EXACTLY like another lesson :)

OpenStudy (anonymous):

and now let us use the property that i wrote before and apply it to there and write this as sqrt(z^2)*sqrt(z^2)*sqrt(z^2)*sqrt(z)

OpenStudy (anonymous):

now could you obtain the final answer?

OpenStudy (anonymous):

yep.........

OpenStudy (anonymous):

if i have anymore Q could you please try and answer them i'll give you best answer everytime :)

OpenStudy (anonymous):

haha no problem just post it anytime

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