Question

Integrate. 1/sqrt(x^2+16)

Answer 1

We have
\[\int \frac{1}{\sqrt{x^2+16}} dx\]
Do you know integration by substitution?

Answer 2

yeah, I think did something wrong because I got \[1/4\ln \left| \sqrt{x^2+16} =x\right|\]

Answer 3

Could you share your work here?

Answer 4

I think I know why it's raised to the 1/4 power right. I think I get it. because if everything it raised to that the numbers that are over 4 go away.

Answer 5

you did u sub? did you learn trig subs?

Answer 6

Yes I did, I think I know my error.

Answer 7

Could you try again? pr you want me to guide you?
@CatLove9

Answer 8

*or

Answer 9

I got it, I forgot about sec^2

Answer 10

@CatLove9 so what did you get this time?

Answer 11

ln|sqrt(x^2+16)+x|

Answer 12

there is a 1/4 missing in the integral. Would you check again?

Answer 13

No there isn't I checked the answer in the book it's right because the dtheta is 4sec^2

Answer 14

got it, sorry :(

Answer 15

It's okay