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differentiation of \(\C_0x\) isn't it 1\(\C_0\)
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\[\huge{C_0x}\] \[\huge{1C_0}\] right ?
Yes you can say that..
Oh k thanks @waterineyes
Welcome dear...
it is wiser though to just say \[c_o\] just like you will in \[1x\]
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Yes .. . I just wanted to show 1 there. . . thanks ! lgba
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