Three vertixes of a convex quadrilateral are fixed. Find the locus of the fourth vertex if the area of the quadrilateral is constant.
I came across a similar question somewhere. Wouldn't it be a line?
um theres several answers i think
what year are u in!
|1 1| |0 1| |x y| |1 0| |1 1| 0.5(1 + 1 - (x + y)) = ? 0.5(2 - x - y) = ? 1 - 0.5x - 0.5y = ? -0.5y = 0.5x - 1 y = -x + 2 Not completely sure if this is correct, but that's what I got.
It would be a line most definitely.
What I did was use an example to see what I got.
Is this multiple choice?
nope.. well the answer says theres three cases to consider. first case answer is y=-2k/a k is constant
I'm sorry...you're gonna have to ask someone else for this one...the only thing I see is 'locus of points' which would mean a type of graph.
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