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Triangle ABC is similar to triangle PQR. Which equation is correct? Posting Picture!
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eq.?
\[\Delta{ACB}(issimilar to) \Delta{PRQ}\]
Oh Sorry!!! The equations!! Hold on!!
i see two angles that are the same so AA postulates?
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You need to find the ratios that will give the same answer. For example for the second one \[\frac{c}{r}\] You have the same side as ratio from both triangle so does that mean \[\frac{a}{p}\] also has the same side and if it does that means the ratio will be the same
since ACB and PRQ are similar.\[\frac {AC}{PR}=\frac {CB}{RQ}=\frac {AP}{PQ}\] Now you can get the ans. by substitiuting the value.
Ok! Thank you!!!
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