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\[\log(x + 2) - \log(x - 3) = \log 6\]
Use here one of the formulas of Log: \[\large Log_x(a) - Log_x(b) = Log_x(\frac{a}{b})\]
Apply this formula on Left Hand Side and tell me what you got..
@pratu043 are you getting what I am explaining to you or not??
\[\LARGE{\log_{} {\frac{x+2}{x+3}}=\log_{}{6}} \]
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There is a little mistake @jiteshmeghwal9
sorry, its x-3
I said there is a little mistake.. Find that mistake... @jiteshmeghwal9
I think @pratu043 is online but not online actually...
so now cross multiply\[x+2=6(x-3)\]
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i think @pratu043 is not there :|
\[\LARGE{x+2 \over x-3}=6\]
\[x+2=6(x-3)\]\[x+2=6x-18\]\[x-6x=-18-2\]\[-5x=-20\]\[x=4\]
Sorry and thanks guys, my mum wanted the computer for a bit.
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