Question

The diagram below shows the map of a mine.

Answer 1

x = 4tan(18)

Answer 2

\[\tan(\theta)=\frac{\text{opp}}{\text{adj}}\]
\[\tan(18°)=\frac{BC}{4[\text{km}]}\]
\[{4[\text{km}]}\tan(18°)={BC}\]

Answer 3

what the question