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Mathematics 10 Online
OpenStudy (anonymous):

PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions

OpenStudy (anonymous):

HELP please explain how :)

OpenStudy (anonymous):

could I get any Idea about computer science? I have some project work this week!!

OpenStudy (anonymous):

Earth-Space Science??

OpenStudy (hba):

1)-7

OpenStudy (hba):

2)2\[\sqrt{11}\]

OpenStudy (anonymous):

you mean 3√11 or 2√22 ????

OpenStudy (hba):

|dw:1342277961301:dw|

OpenStudy (anonymous):

k #3 ?? :)

OpenStudy (anonymous):

-7 is answer

OpenStudy (anonymous):

friend you dont count x in that just count the numbers. like below \[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\] \[3\sqrt{7}-3\sqrt{7}-7\] \[-7\]

OpenStudy (anonymous):

awesome i got that one PLEASE continue muhammad9t5

OpenStudy (anonymous):

yes did you understand?

OpenStudy (anonymous):

yes :) the other ones aren't that simple though:(

OpenStudy (anonymous):

if yes then please dont forget to click on best answer to vote me.

OpenStudy (anonymous):

thanks/.... @Ashley99

OpenStudy (anonymous):

no prob PLEASE keep going muhammad9t5

OpenStudy (anonymous):

muhammad9t5 ??????

OpenStudy (anonymous):

yes whats up?

OpenStudy (anonymous):

friend thats your answer.....

OpenStudy (anonymous):

can you PLEASE help me w/ the other probs too??

OpenStudy (anonymous):

you explain things very well :)

OpenStudy (anonymous):

yes friend i will do my best to help you more..

OpenStudy (anonymous):

friend whats your other question?

OpenStudy (anonymous):

click the attachment it's #2

OpenStudy (anonymous):

friend its just like we do addition 1+2=3 so its same also as below \[\sqrt{11}+2\sqrt{11}\] \[3\sqrt{7}\] its your answer...

OpenStudy (anonymous):

sorry \[3\sqrt{11}\]

OpenStudy (anonymous):

ok that's wat i thought but i doubt myself :)

OpenStudy (anonymous):

#3 Please (you rock)

OpenStudy (anonymous):

friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.

OpenStudy (anonymous):

another check i'm kinda iffy about this lesson it's √3y^3

OpenStudy (anonymous):

#4 I think is- 13p^3√p-2p√p yes or no

OpenStudy (anonymous):

muhammad9t5 ??

OpenStudy (anonymous):

wait friend.

OpenStudy (anonymous):

you still there muhammad9t5 ??

OpenStudy (anonymous):

yes i am

OpenStudy (anonymous):

did you get the Q?

OpenStudy (anonymous):

no i didnt... but i will do it later.

OpenStudy (anonymous):

@Loujoelou i need your help w/

OpenStudy (anonymous):

PLEASE I REALLY NEED HELP NOW

OpenStudy (anonymous):

@Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] HELP SIMPLIFY

OpenStudy (anonymous):

K I just opened the document.

OpenStudy (anonymous):

no not the stuff in the doc the message above!!!

OpenStudy (anonymous):

Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?

OpenStudy (anonymous):

1st term yep

OpenStudy (anonymous):

What about the 2nd?

OpenStudy (anonymous):

nope?

OpenStudy (anonymous):

Yes, you're correct. Do you know how to simplify it?

OpenStudy (anonymous):

friend can we move to 5th??

OpenStudy (anonymous):

@muhammad9t5 sure

OpenStudy (anonymous):

?

OpenStudy (anonymous):

@Loujoelou eh......... please explain

OpenStudy (anonymous):

\[\sqrt{169}-\sqrt{50}-\sqrt{8}\] square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor \[13-5\sqrt{2}-2\sqrt{2}\] \[13-7\sqrt{2}\] is your answer.

OpenStudy (anonymous):

Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us \[2x \sqrt{2x}\]

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