PLEASE SOLVE AND EXPLAIN
Adding and Subtracting Radical Expressions
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OpenStudy (anonymous):
HELP please explain how :)
OpenStudy (anonymous):
could I get any Idea about computer science? I have some project work this week!!
OpenStudy (anonymous):
Earth-Space Science??
OpenStudy (hba):
1)-7
OpenStudy (hba):
2)2\[\sqrt{11}\]
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OpenStudy (anonymous):
you mean 3√11 or 2√22
????
OpenStudy (hba):
|dw:1342277961301:dw|
OpenStudy (anonymous):
k #3
??
:)
OpenStudy (anonymous):
-7 is answer
OpenStudy (anonymous):
friend you dont count x in that just count the numbers. like below
\[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\]
\[3\sqrt{7}-3\sqrt{7}-7\]
\[-7\]
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OpenStudy (anonymous):
awesome i got that one PLEASE continue
muhammad9t5
OpenStudy (anonymous):
yes did you understand?
OpenStudy (anonymous):
yes :) the other ones aren't that simple though:(
OpenStudy (anonymous):
if yes then please dont forget to click on best answer to vote me.
OpenStudy (anonymous):
thanks/.... @Ashley99
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OpenStudy (anonymous):
no prob PLEASE keep going muhammad9t5
OpenStudy (anonymous):
muhammad9t5 ??????
OpenStudy (anonymous):
yes whats up?
OpenStudy (anonymous):
friend thats your answer.....
OpenStudy (anonymous):
can you PLEASE help me w/ the other probs too??
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OpenStudy (anonymous):
you explain things very well :)
OpenStudy (anonymous):
yes friend i will do my best to help you more..
OpenStudy (anonymous):
friend whats your other question?
OpenStudy (anonymous):
click the attachment it's #2
OpenStudy (anonymous):
friend its just like we do addition 1+2=3 so its same also as below
\[\sqrt{11}+2\sqrt{11}\]
\[3\sqrt{7}\] its your answer...
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OpenStudy (anonymous):
sorry \[3\sqrt{11}\]
OpenStudy (anonymous):
ok that's wat i thought but i doubt myself :)
OpenStudy (anonymous):
#3 Please (you rock)
OpenStudy (anonymous):
friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.
OpenStudy (anonymous):
another check i'm kinda iffy about this lesson it's
√3y^3
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OpenStudy (anonymous):
#4 I think is-
13p^3√p-2p√p
yes or no
OpenStudy (anonymous):
muhammad9t5
??
OpenStudy (anonymous):
wait friend.
OpenStudy (anonymous):
you still there muhammad9t5 ??
OpenStudy (anonymous):
yes i am
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OpenStudy (anonymous):
did you get the Q?
OpenStudy (anonymous):
no i didnt... but i will do it later.
OpenStudy (anonymous):
@Loujoelou i need your help w/
OpenStudy (anonymous):
PLEASE I REALLY NEED HELP NOW
OpenStudy (anonymous):
@Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\]
HELP SIMPLIFY
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OpenStudy (anonymous):
K I just opened the document.
OpenStudy (anonymous):
no not the stuff in the doc the message above!!!
OpenStudy (anonymous):
Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?
OpenStudy (anonymous):
1st term yep
OpenStudy (anonymous):
What about the 2nd?
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OpenStudy (anonymous):
nope?
OpenStudy (anonymous):
Yes, you're correct. Do you know how to simplify it?
OpenStudy (anonymous):
friend can we move to 5th??
OpenStudy (anonymous):
@muhammad9t5 sure
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
@Loujoelou eh......... please explain
OpenStudy (anonymous):
\[\sqrt{169}-\sqrt{50}-\sqrt{8}\]
square root of redical 169 is 13 ,
square root of 50 is 5redical2 and
square root of 8 is 2redical2 therefor
\[13-5\sqrt{2}-2\sqrt{2}\]
\[13-7\sqrt{2}\] is your answer.
OpenStudy (anonymous):
Factors of 8= 2*2*2.
|dw:1342281410594:dw|
That is what we would do. That would then give us \[2x \sqrt{2x}\]