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DOUBLE INTEGRATE: Ve^(uv)dudv ... i dont kno what to do with du??
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\[e^{uv} \neq e^u e^v \]
\[e^{u+v}=e^u e^v\]
Recall \[\int\limits_{}^{}e^{cx} dx=\frac{1}{c} e^{cx} +k , c \neq 0\]
Do inside integral first So when integrating with respect to u treat v like a constant :) And then other way around when you get to outside integral
@myininaya sorry, I forgot that :(:(
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