Question

Solve for x: (x – 4)2 = 2

x = 4 ± 2 sqrt2

x = 4 ± sqrt13

x = 4 ± sqrt2

x = 4 ± 2 sqrt13

Answer 1

We have
\[(x-4)^2=2\]
take root both the sides, we get
\[x-4=\pm \sqrt 2\]
Now add 4 to both the sides @kenbaby

Answer 2

use identity\[(a-b)^2=a^2+b^2-2ab\]so,\[x^2+16-8x=2\]\[x^2+16-2-8x=0\]\[x^2+14-8x=0\]