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A data set consists of the following data points: (3,5), (5,8), (6,13) The slope of the best fit line is 2.5. Find the y-intercept of this line.
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the anchor point is going to be the average of the other 3 add em up and divide by 3
(3,5), (5,8), (6,13) ------ (14,26)/3 then use the point slope form of a line y - 26/3 = m(x-14/3)
a little swapping about and we get: y = mx+b; where b is the yint nad equate to: -m*14/3 + 26/3
Ohk. i think i understand!
its been awhile, but i do believe thats how you find the "common" point to anchor the slope to its the average of the others
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I got -3
-2.5*14/3 + 26/3 = -3; me too :)
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