Question

–2(x – 3) ≥ 5 – (x + 3)

Answer 1

solve for x?

Answer 2

find x ?

Answer 3

distribute and simplify both sides first....can you tell me what you get after that?

Answer 4

\[-2 (-3+x)\geq 2-x \]Expand the LHS.\[6-2 x\geq 2-x \]Subtract 6 from each side.\[-6+6-2 x\geq 2-x-6 \]\[-2 x\geq -4-x \]Add 2x to each side.\[2 x-2 x\geq 2 x-4-x \]\[0\geq -4+x \]Add 4 to each side.\[4+0\geq -4+x+4 \]\[4\geq x \]\[x\leq 4 \]

Answer 5

–2(x – 3) ≥ 5 – (x + 3)
you are going to multiply -2 with x and 3
then multiply 5 with x and 3
then you should get
-2x - 6 and 5x+15
then combine like terms

Answer 6

@chikitagee

5-(x+3) is not equal to 5*(x+3)

Answer 7

then what is it @robtobey

Answer 8

≥ 5 – (x + 3) -> ≥ 5 – x - 3)