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-5sqrt2(-4sqrt6)
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\[-5\sqrt{2}\times (-4\sqrt{6})=(-5)\times (-4)\times \sqrt{2\times 6}=20\sqrt{12}\]
and since \(\sqrt{12}=\sqrt{4}\times \sqrt{3}=2\sqrt{3}\) you can write \[20\sqrt{12}=40\sqrt{3}\]
nothing magic here. you can change the order of multiplication. and you can use the idea that \[ \sqrt{a}\sqrt{b}= \sqrt{ab}\] the only nit I have with sat's answer is I would not multiply 2*6 to get 12. I would factor 6 to get 2*2*3 and look for pairs to pull out of the square root.
good point
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