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Write 3^x = 66 as a logarithmic function.
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would it be log(3x)=log(66) log(3) + log(x)=log(66) log(x)=log(66)-log(3) log(x)=log(66/3) log(x)=log(22) x=22
\[x = \log_{3}66\]
\[x = \log(66)/\log(3) = 3.81\]
thank you
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