Question

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t^2 + 704t. After how many seconds does the projectile take to reach its maximum height?

Answer 1

maximum height is when velocity is zero

so take the derivative then equate to zero

Answer 2

do you get that?

Answer 3

\[\large{\frac{u^2\sin^2\theta}{2g}=H}\]

Answer 4

Wait lemme think about the correct way about this .. I do think that equations of motion will be applied here

Answer 5

Ok so here i go with the correct soln