A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t^2 + 704t. After how many seconds does the projectile take to reach its maximum height?

Question

lgbasallote · Answer

maximum height is when velocity is zero

so take the derivative then equate to zero

lgbasallote · Answer

do you get that?

mathslover · Answer

$$\large{\frac{u^2\sin^2\theta}{2g}=H}$$

mathslover · Answer

Wait lemme think about the correct way about this .. I do think that equations of motion will be applied here

mathslover · Answer

Ok so here i go with the correct soln

mathslover · Answer

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