Question

(x+3)(x-3)=-8

Answer 1

Hint: the left side is difference of squares

Answer 2

thanks hero now i know where i am going

Answer 3

do not forget the \[\pm \] at the end...

Answer 4

yes

Answer 5

Technically, you don't really need to use \(\pm\)

Answer 6

@aceace

Answer 7

why it will be x^2=???

Answer 8

\(x^2 - 9) = -8\)
\(x^2 - 9 + 8 = 0\)
\(x^2 - 1 = 0\)
\((x+1)(x-1) = 0\)
x = -1,1

Answer 9

No \(\pm\) involved

Answer 10

but you can just say ....\[x=\pm 1\] much easier and formal...what do you think @hero?

Answer 11

Either method is acceptable. I just either one depending on what mood I'm in.

Answer 12

But here, I was just showing it doesn't have to be done with the \(\pm\). It's always good to know more than one way to solve any problem.

Answer 13

haha true and nicely said