Question

If y=4sinx * 3x^ 2 * 9 then find dy/dx

Answer 1

its (108(x^2)cos x )+ (72*x*cos x)

Answer 2

how come?

Answer 3

@optimus_sai the answer will be
108[ 2x sinx + x^2 cosx ]

Answer 4

@Devanshi first simplify the given eq.
u'll get y = 108* sinx * x^2
then use the product rule:
d/dx (uv) = u v' + v u'

Answer 5

ya its just a small mistake
any way thanks to Vaidehi09

Answer 6

sure, np :)