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log(x+1)=5
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What is the base??
yes!
thats all it says
If base I assume as 10 then: \[\large \log_{10}(x+1) = 5 \implies 10^5 = x+1 \implies x = 10^5 - 1\]
let the base be x.then\[\log_{y}{x+1}=5 \]now change it into exponential form\[y^5=x+1\]solve it from here
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