Question

Find the leg of each isosceles right triangle when the hypotenuse is of the given measure.

Given = 8

Answer 1

assume each leg = x
then using pythagoras theorem,
x^2 + x^2 = (hypotenuse)^2
2x^2 = 8^2
2x^2 = 64
x^2 = 32
x = sqrt(32)
x = 4* sqrt(2)

Answer 2

thats what i got but it says that its wrong

Answer 3

how can that be? have they given u the answer?