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Find the leg of each isosceles right triangle when the hypotenuse is of the given measure. Given = 8
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assume each leg = x then using pythagoras theorem, x^2 + x^2 = (hypotenuse)^2 2x^2 = 8^2 2x^2 = 64 x^2 = 32 x = sqrt(32) x = 4* sqrt(2)
thats what i got but it says that its wrong
how can that be? have they given u the answer?
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