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for the function f(x) = x^2-3x-4, determine g(x) =f(2x)
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\[\Large f(x) = x^2-3x+4\] \[\Large f(2x) = (2x)^2-3(2x)+4\] Simplify from here
oh okay thanks
tell me what you get
4x^2-6x+4
you got it
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what if g(x) = 2f(2x)?
would it be 8x^2-12x+8?
Then you need to find \[\Large 2f(2x) = 2(4x^2-6x+4)\]
you are correct
\[\Large 2f(2x) = 8x^2-12x+8\]
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okay thanks
yw
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