Question

what do i do to find the domain and range of the question?

Answer 1

\[y=2\sqrt{3x+4}-5\]

Answer 2

hint: 3x + 4 cannot be negative

Answer 3

its not negitive..

Answer 4

it would be if for example x = -2

Answer 5

doamain is set of x for which y is defined. Since sqrt of negative number is not defind:
3x+4>0
3x>-4
x>-4/3 is the domain
range will be the values of y which are correspondent to x from the domain:
y=2sqrt0 -5= -5
so range is y> -5

Answer 6

remember there is no real number which is sort of a negative

Answer 7

myko has it

Answer 8

sry, litle correction, substitute > by >=

Answer 9

alright thanks alot.

Answer 10

yw