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Mathematics 10 Online
OpenStudy (anonymous):

If a pro basketball has a vertical leap of about 25 leap. What is his hang time? Use the hang time function v=48T^2. His hang time is _seconds.

OpenStudy (anonymous):

"....about 25 leap" what's that?

OpenStudy (anonymous):

(vertical leap of about 25 inches). sorry, too much homework, trying to hurry

OpenStudy (shane_b):

\[25=48t^2\] Just solve for t.

OpenStudy (shane_b):

You should get \[t=\sqrt{\frac{25}{48}}\]

OpenStudy (anonymous):

Is the answer, 0.7217

OpenStudy (shane_b):

Yes

OpenStudy (anonymous):

Ok, thanks for your help

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