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if cos inverse x/2+cos inverse y/3=z ,then prove that 9x square-12xy cos z +4y square=36 sin square z
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\[\arccos\left(\frac x2\right)+\arccos \left(\frac y3\right)=z\]
\[9x ^2-12xy \cos \left(z +4y ^2\right)=36 \sin ^2( z)\]
like this?
yes . it is..
i bet you have to take a square root at some stage
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do arc and inverse,both signify the same thing?
yer
okay. can you help me in solving out it.at staring of steps?
i dont know what to do
okay.thanks
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