An investment is worth $3518 in 1995. By 2000 it has grown to $5553. Let y be the value of the investment in the year x, where x = 0 represents 1995. Write a linear equation that models the value of the investment in the year x.

Question

paxpolaris · Answer

linear equation: $\large y=mx+b$

at x= 0 y=3518... $\therefore b=3518$
$$\large m={5553-3518\over5-0}$$

anonymous · Answer

here are the choices

A. y = -407x + 7588	

B. y =  x + 3518	

C. y = -407x + 3518	

D. y = 407x + 3518

paxpolaris · Answer

$$\large m={5553-3518\over5-0}={2035 \over5}=\huge 407$$
b=3518

y=mx+b

so, y= 407x+3518

paxpolaris · Answer

D.

anonymous · Answer

thnxx. well explained!