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help me, pleaseee.. For any real number b, let f(b) denote the minimum of the function | sin x + 2/(3 + sin x) + b | find the minimum of f(b), for x and b real...
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| sin x + 2/(3 + sin x) + b | = absolut of sin x + 2/(3 + sin x) + b
i think minimum value occurs when b : -ve sin x : +1
we can setup b as, b = - [sinx + 2/(3+sinx) ] then the minimum value is 0 !!
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