Question

find the derivative of y=lnx/x^2+1

Answer 1

Is this your question?
\[y=\frac{\ln x}{x^2+1}\]

Answer 2

yes

Answer 3

use division rule here
\[\large d(\frac uv)=\frac{vdu-udv}{v^2}\]
\[\large\frac{dy}{dx}=\frac{(x^2+1)\times \frac{d}{dx}(\ln x)-\ln x\times \frac{d}{dx}(x^2+1)}{(x^2+1)^2}\]

Answer 4

Can you do the rest?

Answer 5

i get stuck :(