Question

The 20th term of the series 2 *4 + 4*6 + 6*8+...... is?

Answer 1

\[\huge a_{n}=4n(n+1)\]

Answer 2

The general member of sequence is
\[2n\cdot(2n+2)\]
Let n=20 and get the result

Answer 3

Wat is that

Answer 4

is this in AGP

Answer 5

@satellite73

Answer 6

what means AGP?

Answer 7

Arithmetico - geometric progression

Answer 8

Plzz help me!

Answer 9

Not sure but i think its not

Answer 10

22*24

Answer 11

The answer should be 1680

Answer 12

@satellite73 plzzzz hrlp

Answer 13

@mukushla @klimenkov ur method is correct but hw

Answer 14

@mukushla

Answer 15

oops sorry it should be 40*42 here it is. ..
2n(2n+2)

Answer 16

hw did u figure out the equation

Answer 17

2 *4 + 4*6 + 6*8+ ...
First term = 2 *4 = 2(1) * 2(1+1)
Second term = 4*6 = 2(2) * 2(2+1)
Third term = 6*8 = 2(3) * 2(3+1)

=> General term = 2n* 2(n+1)

Answer 18

thxxx

Answer 19

Welcome :)