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The 20th term of the series 2 *4 + 4*6 + 6*8+...... is?
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\[\huge a_{n}=4n(n+1)\]
The general member of sequence is \[2n\cdot(2n+2)\] Let n=20 and get the result
Wat is that
is this in AGP
@satellite73
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what means AGP?
Arithmetico - geometric progression
Plzz help me!
Not sure but i think its not
22*24
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The answer should be 1680
@satellite73 plzzzz hrlp
@mukushla @klimenkov ur method is correct but hw
@mukushla
oops sorry it should be 40*42 here it is. .. 2n(2n+2)
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hw did u figure out the equation
2 *4 + 4*6 + 6*8+ ... First term = 2 *4 = 2(1) * 2(1+1) Second term = 4*6 = 2(2) * 2(2+1) Third term = 6*8 = 2(3) * 2(3+1) => General term = 2n* 2(n+1)
thxxx
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