In how many ways can a transportation committee of fifteen senators be chosen from the 100 members of the U.S Senate, then a 10 member health committee be formed?

Really sorry for all the questions, my guess is as follows..

Question

In how many ways can a transportation committee of fifteen senators be chosen from the 100 members of the U.S Senate, then a 10 member health committee be formed?

Really sorry for all the questions, my guess is as follows..

anonymous · Answer

So:
100c15 and 85c10 would assumably by the choices  needed..

anonymous · Answer

I just don't know whether to add these values or multiply

anonymous · Answer

general guideline is if you have "or" you add and if you have "and" you multiply
this is very general so don't take it too literally

anonymous · Answer

okay....so..  253338471349988640 x 3129162672636? that seems like an awfully big value...are my nCr things right? :S

anonymous · Answer

you are correct, there are $_{100}C_{15}$ for first one and then $_{85}C_{10}$ for second 
counting principle then says if there are $n$ ways to do one thing and $m$ ways to do another, then the number of ways to do them both is $n\times m$

anonymous · Answer

yes, it is an amazingly large number

anonymous · Answer

http://www.wolframalpha.com/input/?i=%28100+choose+15%29*%2885+choose+10%29 some number of octillions

anonymous · Answer

okay, thank you!!

anonymous · Answer

yw