Question

2x + 10y = -42

-3x + 9y = -81
ELIMINATION METHOD SOMEONE HELP

Answer 1

Multiply the 1st equation by 3 and the other by -2 and solve for y.

Answer 2

Multiply the first one by 3. Tell us what do you get.
Multiply the second one by 2. Tell us what do you get

Answer 3

multiplied by 3 got 16
multiplied the second by 2 and got 24

Answer 4

Multiply the first one by 3
3(2x+10y)=-42
=6x+30y=-126.....(A)
and Multiply the second one by -2
-2(-3x+9y)=-81
=6x-18y=-162......(B)
then use both eqs (A) n (B) and eliminate the common i.e 6x
6x+30y=-126
6x-18y=-162
- + =+ (sign will be changed)
6x will be cancel out and the eq will become as follow
48y=-288
y=-288/48
y=-6
hope u understand it

Answer 5

and by placing the value of " y" in one the equation you will get the value of " x"
2x+10y=-42
2x+10(-6)=-42
2x-60=-42
2x=60-42
2x=18
x=18/2
x=9